Find the pixels you need for a given print size.
Updated July 2, 2026Print size = pixels ÷ DPI.
Multiply the print width in inches by the target DPI, then multiply the print height the same way. The two results are the pixel dimensions the file needs; multiply them together and divide by a million for megapixels.
The fields above default to a 20 × 30 in print. At 300 DPI, the setting most labs use for photo-quality output, that works out to 20 × 300 = 6,000px wide and 30 × 300 = 9,000px tall, about 54 megapixels, more than most single-shot cameras deliver without stitching multiple frames together.
Drop the same 20 × 30 in print to 150 DPI, the tier common for posters viewed from a few feet back, and the requirement falls to 3,000 × 4,500px, about 13.5 megapixels, well inside range for most phone cameras. At 72 DPI, meant for screens rather than paper, the same print only needs 1,440 × 2,160px, about 3.1 megapixels. Push to 600 DPI for archival work instead and the requirement jumps to 12,000 × 18,000px, 216 megapixels, beyond what almost any single consumer camera can produce.
Using this tool's own default print size, here is the pixel requirement at each DPI option in the dropdown:
| DPI setting | Pixels needed | Megapixels |
|---|---|---|
| 600 DPI | 12,000 × 18,000 px | 216.0 MP |
| 300 DPI | 6,000 × 9,000 px | 54.0 MP |
| 150 DPI | 3,000 × 4,500 px | 13.5 MP |
| 72 DPI | 1,440 × 2,160 px | 3.1 MP |
Each row is the same 20 × 30 in print multiplied by the DPI shown, computed directly from the formula above.
Multiply each print dimension (inches) by your target DPI. 20×30 in at 300 DPI needs 6000×9000 px.
About 28.8 MP at 300 DPI (4800×6000).
Software upscaling helps a little, but it can’t add true detail.
150 DPI is often fine for posters viewed from a distance.
Phone images may lack the pixels for big prints at 300 DPI.